Mathematics
Junior High
Solved
教えてください！
問 5 次の式の同類項をまとめなさい。
(1) 4a+7a
= 11a
(3)
5
6
-ab²_
3
8
ab²
(5) -462+66²-262
= 6
(7) a-2ab+9a-4ab
= 10a-6ab
(9) 5a+3b-8c-2a+4b
= 3a +7b-8c
(8)
(2) 5x2−8x
= - 3x1
(4)
(6)
x+2x+3x
= 6x
2
3
2
-xy
11
15
-xy+
5
6
-xy
(---)+
(8) -3x²+6x-12-6x+4x²
2
-x²² - 12
(8)
7
(10) y² + 2xy
31²-6x² +-
Answers
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