公式
(a+b+c)²＝a²+b²+c²+2ab+2bc+2ca
を利用すると、
(a-b+c)²＝a²+(-b)²+c²-2ab-2bc+2ca
＝a²+b²+c²-2ab-2bc+2ca
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公式
(a+b+c)²＝a²+b²+c²+2ab+2bc+2ca
を利用すると、
(a-b+c)²＝a²+(-b)²+c²-2ab-2bc+2ca
＝a²+b²+c²-2ab-2bc+2ca
Users viewing this question
are also looking at these questions 😉
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