Mathematics
Senior High
どうしてこうなるのか意味がわかりません。ムカついてボールペン破壊しました
よって
Sn=Σak= Σ (3k-
k=1
k=1
n
n
=9k²-12 Σ k +421
k=1
k=1
k=1
=9. n(n+1)(2n+1)-12)
=½n{(6n²+9n+3)−(12m+ 183 413)
=½n(6n²-3n−1)
(2) ak=1+4+7+······+{1+(k-1).3}
=1/1k{2.1+(k-1)・3}
1
=/(3k²-k)
2
(S) (S.
よって 1/12 (3k-k)
n
n
Sn= Σ ak= Σ
k=1
k=1
k=1
3 n
n
= 2²22 R²-1² - R
Σ k
k=1
2k=1
=
31
●
26
-n(n+1)(2n+1) — 1/2 + 1/{√n(n+
2
1
= n(n+1){(2n+1)-1}
=1/√n²(n+1)
=1/1/2+1/(-1/2)+1/(-1/21)
k
1/12 (1-(- -1/2)^}
1- (-/1/2)
(3) + + (−1)
Ak
-
1/3 {¹-(- - -/- ))}
Answers
No answer yet
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉