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y
= ax² + ax + a - 1
= a(x + 1/2)² - a²/4 + a - 1
頂点は ( -1/2 , -a²/4 + a - 1 )
Mathematics
Senior High
Solved
二次関数の頂点を求めるものです。(10)が分かりません。共通因数aでまとめるところまで行きましたが、ここから先が分かりません。わかる方、途中式から答えまで教えてください。
(10) y=ax² + ax+a-1
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