Mathematics
Senior High
-9log₃√7はなぜlog₃7^-3/2となるのですか？
(4) 2log3441-910g3√7-log
pagol
31
6
27
343
wagol=d.gol 10)
9
(4) ♬â†1 (5x)=log3 (3².7²)²+10g3 72+10g3
{(3)
=log3 (34.74) +log3 72+10g3(3-2-72)
=logs (3¹-1-74-+2) = log:37 = 2
9
11/0
6
7
BS)(S
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