Mathematics
Senior High
Solved
赤のところで終わっていても大丈夫ですか??
(3) ab(a-b)+bc(b-c)+ca(c-a)
=a²b-ab²+bc(b-c)+c²a-ca²
=(b-c)a²-(b²-c²)a+bc(b-c)
=(b-c)a²-(b+c)(b-c)a+bc(b-c)
=(b-c){a²-(b+c)a+bc)
=(b-c)(a−b)(a-c) |
=-(a-b) (b-c) (c-a)
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