Mathematics
Senior High
Resolved
(3)の解き方教えてください。
3 sin+cos 0 = 12 のとき、次の式の値を求めよ。
(1) sin cos 0
(2) sin ³0+cos³0
1
(5)
sin cos 0
tan 0
(!). Sin ³0 + 2 sin cos. A + cos² A
(4) tan@ +
43
4.
(3)
1 + 2x
2x = 4
3
4
x=3
2x =
8⁰
Sin cos A
-
+
4
FY
1/2 x 1/1/0
8
N₁
m/00
8
(²) (sin A + cos 0) (sing-singcas A + COSA)
1/12 (18
8
8
(3) sin¹0+ cos¹0
(6) sin 0, cos
5
4
16
5
Sin³A + Cos³ A = 16
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