Mathematics
Senior High
Resolved
どのように展開するのですか?
1
π
xの関数f(x) = "(t+x.cost)' dt がxの2次関数で
この最小値とそのときのxの値を求めよ。
f(x) = ² (²+2x-tcos2t + x² cos²2 t)dt
2
=f² rdt + 2xf²1cos21dt + x²fcos 21 dt-
tdt...
(C(定数)
B(定数)
A(定数)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉


ありがとうございます🙇🏻♀️՞