Mathematics
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(ac+bd)二乗-(ad+bc)二乗
途中計算を教えてください。

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(ac+bd)²-(ad+bc)²=(ac)²+2abcd+(bd)²-(ad)²-2abcd-(bc)²=(ac)²+(bd)²-(ad)²-(bc)²=a²(c²-d²)-b²(c²-d²)=(a²-b²)(c²-d²)=(a+b)(a-b)(c+d)(c-d)

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回答ありがとうございます。
解くことができました!ありがとうございました。

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