Mathematics
Senior High
Solved

=(a²-b²)(b-c)
の(b-c)がどこから来たのかわかんないです💦

(2) a2b+b2c-b³-a²c =(62-a²)c+b(a²-b²) =(a²-b²)(b-c) 11-28+8 =(a+b)(a-b)(b-c)()
数ⅰ 因数分解

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