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(2)の解き方考え方を教えて欲しいです

24 例 2.10.5. 次の値を求めよ. 2.10 逆三角関数 (1) sin (Sin (2) cos (Sin 2 3

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sinx=1/3とできるので問題はcosxの値を求めれば良いことになります。よってcosx=√1-sin^2xを計算して2√2/3です。

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