左辺を因数分解すると
(x－3)(x－a)＜0
x＾2の係数が正だから、
①3≦aのとき
整数解は4、5の2個になればよいので
5＜a≦6
②a＜3のとき
整数解は1、2の2個になればよいので
0≦a＜1
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![(2)[1]の式はなぜこうなるのでしょうか？
解説お願いします🙏🏻 - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1810073/thumb_l_webp_1717B3E3-8A84-49A5-82D1-466207496D96.webp?Expires=1787240632&Signature=TSzxTsUwubSJUyBD-ELnbHpdJa~s4mmd30-B0IKnhg-HanF2dROlh8vx5Aze-GSWINiTinLQ2yUEZ6ieJ6dOwqjg-KumAq6kCBtoJGcnDDohxTvoeRfM-UHekVKv1ZJV~Pn~7FHzwNo0b-L5cFbx0i0N0~RNht-FCX9JnFLo1ti-1JeGqxpWiE-J51X~Tk3Ed5WoGgoGiRNz--IREDRn425NYzVADQxBEVNZV8kf4NJzm7yUokeTFVm-HwGnx3eKcOSo-zO9ikBqc7mXEdNHrK6ejhGUfL72q7M1OIPF-O~iPQHOvatYU~tMYlj6Yc3Cs7BDiLrDdf8BoiKzwTsuSg__&Key-Pair-Id=K2W722D70GJS8W&Expires=1787240632&Signature=qJaZEFXyya0591uzCHRzKLMryLGorMUDwMzIoPR~jjwXeaNmKIxm8HPDULjuC1zrPey0lJwVqTNcxiLSjmrCYdo1GqDjC3R2jnnCCou~bRk4MbJgD1WsejwroBcdtZ8yUiE90cwnbhGnR3sI9TOI2sa5hEXv9hDQL~Ebqp4LSzhua0Zfr~h11WifV9oPxB2baWm6BCoZkNWvNKpbn32yah1v9a7ybWVWbCPgpwrPSGSt9wo69ya7SVR~8eKUwmVOkuCRUENFR6xBPhv6AeNnGhr5oVglBWVxXiMX5ndOQQWQMupinFO~r52Q6QvQe8K~-KFrMOZradUaE-9LkTSHDg__&Key-Pair-Id=K2W722D70GJS8W)
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