Mathematics
Senior High
（2）で分子にもともと2があるのに部分分数分解した時に1になるのはなぜですか？
8─数学Ⅱ
練習 次の計算をせよ。
③ 12
(1)
1
+
(x-1)xx(x+1) (x+1)(x+2)
2
2
(2)
+
+
(n-2)nn(n+2)
(1)(与式)=(2-1)+(-)(-1)
1
1
3
=x-x+2=(x-1)(x+2)
(与式)=
(2) (40)-(2-1)+(+2)+(+2+4)
1
n
n
1
n-2
n+4
6
(n-2)(n+4)
←
2
(n+2)(n+4)
=
(x-1)x
x-(x-1)
(x-1)x
1
1
x-1
x
他の項も同様。
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