Mathematics
Senior High
Solved
どうやったらこの式になりますか??
⑥(2) a1 = 1, 3an+1
=
2an+3.2η-1
2
⇒an+1
=
3an+2n-1
an+1
2
an
両辺を 2n+1で割ると
+
2n+1
32n+1
an
1
=
2n
= bn とおくと bn+1
=
3
bn +
4
bn+1 - 3/3 = 1½ (b − 3)
8
bn
{ bn - 2 } は初項 by
-
-
-
8
3-8
bn
bn
-
=
3
8
=
1
8
1 + 3n
8.3n-1
n-1
と変形できる。
27-1 1 an 1
=
+
2n+1 32n 4
a1
3 1
=
公比
21
8
8
1/3の等比数列
an
1+3n
(3n+1)2n-3
an
=
2n
8.3n-1
3n-1
Answers
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