Mathematics
Senior High
Y=2x²+4x+1(0≦x≦1)の最大値最小値を求めよという問題です。
何故x=0で最小値1になるのか詳しく解説お願い致します。
1-9-6-3
とこ
x=1のとき最大値な-7
x=-1のとき最小値-1
y=2x²+42+1 (0 ≤x≤1)
Y=2(x+2)+1
y 7 =
2
7=2(x+1)² = 2+1
1=2(x+1-1
頂(-1,-1)
下の凸
2x114x1+1
2+4+1=7
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉