✨ Best Answer ✨
i+1/i+i/(1+i)
=(i^2)(1+i)/(i(1+i))+(1+i)/(i(1+i))+(i^2)/(i(1+i))
=(-(1+i)+(1+i)-1)/(i(1+i))
=-1/(i-1)
=1/(1-i)
=(1+i)/((1-i)(1+i))
=(1+i)/(1+1)
=(1+i)/2
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