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(x+2y)^2
=x^2+4xy+4y^2
=(x^2+4y^2)+4xy
=16+4×1
=20
(x+2y)^2=20
x+2y=√20=2√5
Mathematics
Senior High
Resolved
教えて欲しいです🙏
5x2+4y2=16,xy=1を満たす正の実数xyがある。
(1)(x+2y) の値を求めよ。 また、 x+2y の値を求めよ。
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