✨ Best Answer ✨
r=√{(√3)²+3²}
=2√3
sinθ=3/2√3=√3/2
cosθ=√3/2√3=1/2
より、θ=π/3
よって、
2√3・sin(θ+π/3)
(3)やり方教えてください!
✨ Best Answer ✨
r=√{(√3)²+3²}
=2√3
sinθ=3/2√3=√3/2
cosθ=√3/2√3=1/2
より、θ=π/3
よって、
2√3・sin(θ+π/3)
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