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2行目から計算間違いしてますよ

(1-3i)³-2(1-3i)²-a(1-3i)+b
=(1-9i+27i²-27i³)-2(1-6i+9i²)-a+3ai+b
=1-9i-27+27i-2+12i+18-a+3ai+b
=(1-27-2+18-a+b)+(-9+27+12+3a)i
=(-10-a+b)+(30+3a)i=0

-10-a+b=0、30+3a=0 を解いて、
a=-10、b=0

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