Mathematics
Senior High
Resolved
どうやって計算しているか教えて欲しいです🙇♀️🙇♀️
(3) 2n3+3n2-5n=n(n-1)(2n+5)om) (S)
(e bom) == n(n-1)(2(n+1)+3)+2
=2(n-1)n(n+1)+3(n − 1)n
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これの3番です!