✨ Best Answer ✨
AB兩點的中點等於垂足座標(1,0)
設B點座標為(a,b)
中點座標(0+a/2 , -1+b/2) = (1,0)
得到B點座標為(2,1)
✨ Best Answer ✨
AB兩點的中點等於垂足座標(1,0)
設B點座標為(a,b)
中點座標(0+a/2 , -1+b/2) = (1,0)
得到B點座標為(2,1)
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