✨ Best Answer ✨
|x|<k
⇔-k<x<k
より、
|3a-1|<2√2a
⇔-2√2a<3a-1<2√2a
⇔3-2√2<a<3+2√2
Answers
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✨ Best Answer ✨
|x|<k
⇔-k<x<k
より、
|3a-1|<2√2a
⇔-2√2a<3a-1<2√2a
⇔3-2√2<a<3+2√2
Users viewing this question
are also looking at these questions 😉
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