✨ Best Answer ✨
(以下 ∑ 都是 i=1 到 i=n)
∑ [(xᵢ - μ)²]
= ∑ [ xᵢ² - 2xᵢμ + μ² ]
= ∑ [ xᵢ² ] + ∑ [ -2xᵢμ ] + ∑ [ μ² ]
= ∑ xᵢ² - 2μ ∑ xᵢ + nμ²
= ∑ xᵢ² - 2μ (nμ) + nμ²
= ∑ xᵢ² - 2nμ² + nμ²
= ∑ xᵢ² - nμ²
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