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(xy+yz+zx)²
=x²y²+y²z²+z²x²+xy²z+x²yz+xy²z+xyz²+x²yz+xyz²
= x²y²+y²z²+z²x²+2xyz(x+y+z)
Mathematics
Senior High
Resolved
2枚目の条件のやつ使った変形の式教えてほしいです🙇♀️
XY* + **Z + Zx²
x+y+z=4, xy+yz+zx=2, xyz=5.
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