✨ Best Answer ✨
Kp={4α²/(1-α²)}×P
両辺1-α²倍
(1-α²)Kp=4Pα²
Kp=Kpα²+4Pα²
=(Kp+4P)α²
α²=Kp/(4P+Kp)
α=√{Kp/(4P+Kp)}
という流れです
✨ Best Answer ✨
Kp={4α²/(1-α²)}×P
両辺1-α²倍
(1-α²)Kp=4Pα²
Kp=Kpα²+4Pα²
=(Kp+4P)α²
α²=Kp/(4P+Kp)
α=√{Kp/(4P+Kp)}
という流れです
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なるほど!ありがとうございました!