f(x)＝x³ + ax +bとおく
(1、2)より2＝1 + a +b⇔ a +b＝1・・・①
f’(x)＝3x² + a
よって(1、2)の接線は
y＝(3 + a)(x–1) +2
(1)(0、0)より a＝−1、b＝2
(2)傾き4より a＝1
①よりb＝0
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