✨ Best Answer ✨
三角形ATDにおいて余弦定理より
(AT)^2 = 8^2 + 4^2 - 2*8*4 cos(角ADT)
=144/5
AT = 12*√5 / 5
✨ Best Answer ✨
三角形ATDにおいて余弦定理より
(AT)^2 = 8^2 + 4^2 - 2*8*4 cos(角ADT)
=144/5
AT = 12*√5 / 5
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