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y=ax^2+bx+cとおく。
平行移動なのでa=3
またx軸方向に-2,y軸方向に5だけ平行移動するので
xにx+2,yにy-5を代入して
y-5=3(x+2)^2+･･･
y=･･･
あとはxの係数と定数=0になるb,cを求めると答えになります
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ありがとうございました！