sin²(180-θ)=sin²θ・・・①
sin²(90-θ)=cos²θ・・・②
①、②より
sin²(180-θ)+sin²(90-θ)=sin²θ+cos²θ
=1
sin²(180-θ)=sin²θ・・・①
sin²(90-θ)=cos²θ・・・②
①、②より
sin²(180-θ)+sin²(90-θ)=sin²θ+cos²θ
=1
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わかりました!ありがとうございました🙇♀️