Answers

t=log₂x
y=(log₂x²)(log₄x-log₄16)+8
log₂x²=2log₂x、log₄x=(log₂x)/(log₂4)=1/2log₂xであるから
y=(2log₂x)(1/2log₂x-2)+8=(log₂x)²-4log₂x+8=t²-4t+8

これでどうでしょうか?

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