Mathematics
Senior High

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Answers

tan{θ+(π/4)}=-√3

θ+(π/4)=xとすると、

tan(x)=-√3

x={(2π)/3}+kπ

(k∈Z kは整数)

θ+(π/4)=x

θ=x-(π/4)

={(2π)/3}+kπ-π/4

={(8π)/12}+kπ-3π/12

={(5π)/12}+kπ //

(k∈Z)

わかめ

ありがとうございます!

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