Mathematics
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因数分解の答えと途中式教えてください!

(3③ 2⑫十c)*十0c二の?十c(@十の2ー420c

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✨ Best Answer ✨

a(b+c)^2+b(c+a)^2+c(a+b)^2-4abc
=ab^2+2abc+ac^2+bc^2+2abc+ba^2+ca^2+2abc
+cb^2-4abc
=(b+c)a^2+(b^2+2bc+c^2)a+bc(b+c)
=(b+c)a^2+(b+c)^2a+bc(b+c)
=(b+c)(a^2+(b+c)a+bc)
=(b+c)(a+b)(a+c)

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