三角形ABCに正弦定理を用いて80/sin120=AD/sin45
よってAD=160/√6
三角形ACDは1:2:√3の三角形だからCD=
160/√6×√3=80√2
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三角形ABCに正弦定理を用いて80/sin120=AD/sin45
よってAD=160/√6
三角形ACDは1:2:√3の三角形だからCD=
160/√6×√3=80√2
Users viewing this question
are also looking at these questions 😉
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