✨ Best Answer ✨
分子分母に×(2-i)で
(2-i)²/(2+i)(2-i)
=(2²-4i+i²)/(2²-i²)
=(4-4i-1)/(4+1)
=(-4i+3)/5
だと思います
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✨ Best Answer ✨
分子分母に×(2-i)で
(2-i)²/(2+i)(2-i)
=(2²-4i+i²)/(2²-i²)
=(4-4i-1)/(4+1)
=(-4i+3)/5
だと思います
Users viewing this question
are also looking at these questions 😉
ありがとうございます！
理解できました！
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