y=ax^2+bx+cのグラフを
x軸方向にm,Y軸方向にnだけ平行移動させたグラフの式の公式は
y-n=a(x-m)^2+b(x-m)+c
今回の問題ではY軸方向に-4ですので
-n→-(-4)となります
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y=ax^2+bx+cのグラフを
x軸方向にm,Y軸方向にnだけ平行移動させたグラフの式の公式は
y-n=a(x-m)^2+b(x-m)+c
今回の問題ではY軸方向に-4ですので
-n→-(-4)となります
Users viewing this question
are also looking at these questions 😉
![基本例題の[2]についてです。ここの条件ですが、
a/3<=1<=4a/3とありますが4a... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1810404/thumb_l_webp_70236300-B387-4A8D-A246-76C58E626EEE.webp?Expires=1787911762&Signature=iYOMaI1x6ZERALe7swp6Ip8xAV1rimFEdmPlsT~RwJLZU9W1upiwbXl-pNQ3YoI3mLfk9pkAHq6By7ViZC53bFUtB-Z7kew0mDgOA~yibFZ7NjiBgTQohg4y4GPhVBiRg8CwSr8r-h6daNmMLjkZfTepYYLEC0Vhs70kzyKPq6jdTFqhHc4sQqyUk2hPwSsluY8Ucqo6QLLnYOmzxkxpFiCxhuA7gib3KRIcaMEmt3oaWOCw9U~HymlRoCle2f-oXigUU3hcGsPMfVVSVsN0aKnhpBc2qoFKmVZTQ8rwerWJkjnOJQzyIi7wLbqOZ5fyJxNHe1Nfu6UR3bj4kCRXhA__&Key-Pair-Id=K2W722D70GJS8W&Expires=1787911762&Signature=ttvnQL0n7QTkUMdEN8N7xo5FCQGaOhBwHA9LuS-QWtc2btxSZ~DS9vBvUb6Tv6GEK7SggogDTGvnXIFBIcjn8UWqaxYHYL3oIgMmK2PT3mYoNbdc97DNZtcnU7PZn5SZkq5bk7uR4ryc3aMWM2aHufEmrPhw1i3eEUdAtRFGbOZUAyOog6g9V4GI0ZcKPwmo7NvinJJHjmuN7QX8tJHfZKmuzg4Mt8PDTvYTDx6MUdD5uemt7e8hQqq-i91vx67gUxxYrDZsSgULLtoqAQkEP8XfahxxfDY-YiNWEror9Frz9sZ9agrMxzeR93LLbv73pFx8LTXB5WeTodYH17d7Hw__&Key-Pair-Id=K2W722D70GJS8W)
個人的にはy-nの部分が好きではないので、
右辺に移項して、y切片みたいな形にして覚えてます(y=a(x-m)^2+b(x-m)+c+n)