Mathematics
Senior High

この計算の途中式を教えてください!!

Answers

(1+√2i)³

=(1)³+3(1)²(√2i)+3(1)(√2i)²+(√2i)³

=1+3√2iー6ー2√2i

=-5+√2i

^_^

ありがとうございます!

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