✨ Best Answer ✨
変数の間に依存関係はないので, 下のように計算できます.
(∫[0->1]√xdx)(∫[0->4]√ydy)
={(2/3)x^(3/2)}|[0->1]*{(2/3)x^(3/2)}|[1->4]
=28/9.
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
✨ Best Answer ✨
変数の間に依存関係はないので, 下のように計算できます.
(∫[0->1]√xdx)(∫[0->4]√ydy)
={(2/3)x^(3/2)}|[0->1]*{(2/3)x^(3/2)}|[1->4]
=28/9.
Users viewing this question
are also looking at these questions 😉
![基本例題の[2]についてです。ここの条件ですが、
a/3<=1<=4a/3とありますが4a... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1810404/thumb_l_webp_70236300-B387-4A8D-A246-76C58E626EEE.webp?Expires=1787737168&Signature=RQ~pjjUP~RIv-mzggpW~SlxtJOtj0meh6wCc3bCDRMAFB2OS-j~z6VMFgHZ3~lgh0aEneNqszI~5ZaO3pITxfkXPBHx1ksydIxmxj5K67z1ZEqiShOW8lWSpldx5WCCSxblqQcptbgIVfuHiv9Jwb1FjAfX7lxsUpUOHekgnPsDmPMdfYoajbF-zLjXFn3MzbEvkiaUguXGGRgMGfwtfXPpEBm-QpUqoMXjHDrHou-TirgGXjCoagVyhG1jdagY3ex4Mj0AZhsB7QjniKoYsuTdIFg5jtxNi2dKcRN8T8p26xuRnowg5JO4bvlxSRpY0-vKtcwuoxSGZnEgVhUUgxw__&Key-Pair-Id=K2W722D70GJS8W&Expires=1787737168&Signature=YpAP303sPENz8sEy8MFpAmsvlGEJVFs3i1Aj~rJOAiErrD5YszR-3CidLKQdQwpA0avwGp3eHiNdCOtsrExq64pAOmECZfgli1Nq9doYjVajXWCQfCt-U2ql2ff7bXuUoTtScDYeapHOxGRtoI-pUS5QTug7OWakJ65lD7trMpZywvpRkRtfJboZBpOnxDwVuvVqOK341Q~rTYUlDx6yWGLsZkJzCkq7u4oCqqhU2TSa~0qJ1cvNeb6BRmT7-SQXPYo0cCh7dwWaBA3fmWp0bDQa2~OetSq3YjLZ2RSRCv0dHLYCaAo9z~PscC5v7bCFc66v0jItGpOAbWSg85fv7A__&Key-Pair-Id=K2W722D70GJS8W)
見にくいので手書きで解説してくださったらベストアンサーを差し上げます。