Answers

やり方は上のものと同じです
Σ[k=1,n]{(k+1)^4-k^4}=Σ[k=1,n](4k^3+6k^2+4k+1)
左辺=(n+1)^4-1
右辺=4Σ[k=1,n]k^3+Σ[k=1,n](6k^2+4k+1)
よって
4Σ[k=1,n]k^3=(n+1)^4-1-Σ[k=1,n](6k^2+4k+1)

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