sin^2θ+cos^2θ=1より
cos^2θ=1-4/9=5/9
90°<θ<180°よりcosθ <0
よってcosθ=√5/3
あとはtanθ =sinθ/cosθ に代入すればtanθが求まり
それをイにあてはめると答えが出ます。
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sin^2θ+cos^2θ=1より
cos^2θ=1-4/9=5/9
90°<θ<180°よりcosθ <0
よってcosθ=√5/3
あとはtanθ =sinθ/cosθ に代入すればtanθが求まり
それをイにあてはめると答えが出ます。
Users viewing this question
are also looking at these questions 😉
