Mathematics
Senior High
(2)についてなのですが、なぜ、外角の二等分線だとBE:ECとAB:ACの比が一緒になるのですか？
(2) AE は 乙BAC の外角の二等分線だから
BE : EC三AB : AC 私
9 3
ー9 : 3三3 : 1 に0
CK
人A
よって, CE=信BC=4
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