Answers

Xの抵抗をxΩ、電源電圧をE Vとすると、直列回路なので
①抵抗C(12Ω)のとき
 E=3.0+0.25x
②抵抗D(16Ω)のとき
 E=3.2+0.2x

3.0+0.25x=3.2+0.2x
0.05x=0.2
x=4Ω

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