✨ Best Answer ✨
(与式)=6+3・1/6 n(n-1)(2n-1)+9・1/2 n(n-1)+6(n-1)
=1/2 n(n-1)(2n-1)+9・1/2 n(n-1)+6n
=n/2{(n-1)(2n-1)+9(n-1)+12}
=n/2(2n²+6n+4)
=n(n²+3n+2)
=n(n+1)(n+2)
いえいえ!!
□のとこの計算が何回やっても答えと一致しないので教えてください
✨ Best Answer ✨
(与式)=6+3・1/6 n(n-1)(2n-1)+9・1/2 n(n-1)+6(n-1)
=1/2 n(n-1)(2n-1)+9・1/2 n(n-1)+6n
=n/2{(n-1)(2n-1)+9(n-1)+12}
=n/2(2n²+6n+4)
=n(n²+3n+2)
=n(n+1)(n+2)
いえいえ!!
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