✨ Best Answer ✨
何を仮定しているかにもよりますが、結合律、交換律、吸収律を認めれば
(p∧q)∧(p∨r)
⇔(q∧p)∧(p∨r)
⇔q∧(p∧(p∨r))
⇔q∧p
⇔p∧q
となります
p∧(p∨r)⇔p ですよ
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
![x>0という条件をつけなくていいのはなぜですか？？例えば⑴の[2]のとき、もしxがマイナス... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1803395/thumb_l_webp_01E8B167-DD37-4DC9-888B-69652610F6E4.webp?Expires=1779688140&Signature=gcV5PKNG7yas1JK6GqXxd-usGNVThUUhox-VjvKUmM1HG7mkzW~0wQNcQtcdbqThef8RZ7Xb~OQr8OrfEV5wP~mwRmSknL~msg0VOUK6LR0Bpm~UxemHJMuAGG0zN10qislPOv2Pw2o9LgsXkyL5OioR4CImZ5M5Ob92c8DXF6vkMqROj6vlnV4s5SPNsSFPDniflrL2t8MUQ2bSg-nW9uDvN8zU5XaPbDfnAA~pZq2YnVhCXjAeONCx6tXcvGJO8sQShJdJYu6qRKng0uRVViKQvrVkLQkd6jdHGyzpRw1~rArcAWWmXy394YbNfUg-vTMCCe0m0CHfF1aZMe-P4Q__&Key-Pair-Id=K2W722D70GJS8W&Expires=1779688140&Signature=G9fRP99e-u0WgSHWcCU64nYnn3S~eyqjiBhNaQJtMDr0cTpxl-JMJsh5Qz~W96bJ7~qUkQvEHtHXJ5-0c93ANynsPOArgBj6z8sJos2f324rrMbShUef1eAuhVXuysOyoRo61b00LgKV3hKZYD-6mtYst1~IBYH2EUPat9-32yrp~md8x6LkGIJcBGS8PoE-ojMMvIWY1IfQRPLKsxClGctIQq-7hD9kGDTjIjktyvGt-p3gcFV~vPsFbwZCBhRFYVVu9LzRVVlIphmeppwSi-qm6R03QrOVFvq1PNKnF0obyzcWcC9nSBYuNhEVMWuRuO92Vqa16Ipb6PH9o2dsUQ__&Key-Pair-Id=K2W722D70GJS8W)
rはどこへ？条件不足では？