✨ Best Answer ✨
s^2=1/3{(x1−x‾)²+(x2−x‾)²+(x3−x‾)²}
=1/3{(x1²+x2²+x3²)−2x‾(x1+x2+x3)+3(x‾)²}
=1/3(x1²+x2²+x3²)−2x‾×1/3(x1+x2+x3)+3×1/3(x‾)²}
=x²‾−2(x‾)²+(x‾)²
=x²‾−(x‾)²
この問題の答えを教えてください🙏🙏
✨ Best Answer ✨
s^2=1/3{(x1−x‾)²+(x2−x‾)²+(x3−x‾)²}
=1/3{(x1²+x2²+x3²)−2x‾(x1+x2+x3)+3(x‾)²}
=1/3(x1²+x2²+x3²)−2x‾×1/3(x1+x2+x3)+3×1/3(x‾)²}
=x²‾−2(x‾)²+(x‾)²
=x²‾−(x‾)²
Users viewing this question
are also looking at these questions 😉
ご丁寧にお答え頂きありがとうございます!🙏