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✨ Best Answer ✨

s^2=1/3{(x1−x‾)²+(x2−x‾)²+(x3−x‾)²}
=1/3{(x1²+x2²+x3²)−2x‾(x1+x2+x3)+3(x‾)²}
=1/3(x1²+x2²+x3²)−2x‾×1/3(x1+x2+x3)+3×1/3(x‾)²}
=x²‾−2(x‾)²+(x‾)²
=x²‾−(x‾)²

ね ね

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