例えば、
2*4*4*4 = 2*4^3 = 2*2^(2*3)
1/2 * 1/2 = 1/(2^2) = 2^(-2)
なので、
2*4^(n-1)
= 2*2^(2(n-1))
= 2*2^(2n-2)
= 2^(2n-2+1)
= 2^(2n-1)
です。
例えば、
2*4*4*4 = 2*4^3 = 2*2^(2*3)
1/2 * 1/2 = 1/(2^2) = 2^(-2)
なので、
2*4^(n-1)
= 2*2^(2(n-1))
= 2*2^(2n-2)
= 2^(2n-2+1)
= 2^(2n-1)
です。
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