✨ Best Answer ✨
対称式なのでx+y=(√2+1)^2+(√2-1)^2=6, xy=1を先に計算しておきます.
あとは与えられた式をx+y, xyで表す方法を考えればいいです.
(2)x^2+y^2=(x+y)^2-2xy=6^2-1=35.
(3)(2)の結果を使うと, x^4y^2+x^2y^4=(xy)^2(x^2+y^2)=35
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
![基本例題の[2]についてです。ここの条件ですが、
a/3<=1<=4a/3とありますが4a... - 1](https://d1e9oo257tadp1.cloudfront.net/uploads/qa_question_image/file/1810404/thumb_l_webp_70236300-B387-4A8D-A246-76C58E626EEE.webp?Expires=1787749560&Signature=Xa-BrB8xlD9QG-5PaiRSLb~56C8SbBJcCFVx6sJiigDzpCS1LXWTYhm8jqBKdg0~UeAGftJww1~RHPnl9uGDX2xmPaBB46U0HKzpq~gIV2s-s9z8S4DPzH3vrCX8zWY4m25Oh8riqT2tbw~48163CXPV1vU14~tUb9DFFhpfnT9FpGzJ3IUNsollhNMZP~B4WbsflAbYYEae5en7RyLNWqMa8t3apP9Fn9pRQREPlNNCA8J99tO6U8QR6Turd-7SGBWmi8vufxEsxw93XJ~X9LI2xWq7pK6YglaNIik-Aenn6s7ZHTkL8zod8vuo30Ds9KUvwyzj85ld6wL91EZebg__&Key-Pair-Id=K2W722D70GJS8W&Expires=1787749560&Signature=xen~vzRj5BjOvQuRH8HsZ0SQCl0SurqA7hYsbDEhti3EUFcJPV8bdhFfDCLWZZynp63VnI8w-oBrlKYxp6S99t~fEI-LDdDIhc5ABaFCNi61x~c4mWEG86dWiYmoT5NjOh3kf7ZfBUJwC4S2GG7VlawIrk5sAHvvTIYB1xAGjvpa0nI~iKW8rw9fKARGgM7PICLOzgBpYRx1Nf~ytbBsOnkpx8xWW2WLGpfCflKHXIn1aPQyTTm13uYa2EkwyYWrHTbXhUs~GkJ4qe1UfZp4uPg5RL0b0TLtZedR-jDcnGdv6Puf7FR-wlzRtRH9ryehaQPXPyupHn06kdZKDfK~hQ__&Key-Pair-Id=K2W722D70GJS8W)
解説がとても分かりやすかったです。
ありがとうございます！