Grade

Subject

Type of questions

English Senior High

英語の共通テスト対策の問題です。 答えがあっているか、間違っていたら答えを教えてください🙇‍♀️

第2問対策 意見文の読み取り ③ No. Name Class Tomom 目標解答時間: 7分 共通テストドリル リーディング 改訂第5版 Your English teacher gave you an article to help you prepare for the debate in the next class. A part of this article with one of the comments is shown below. Net Shopping: Convenient but Addictive By Tony Sutton, Philadelphia 12 June 2019 9:20PM Internet shopping is very convenient. At night or when it is raining or snowing. 1.66 billion people (in the world) are estimated to have used the Internet for shopping in 2017.) In the same year, you can buy things comfortably from your room. total sales of online retail amounted to 2.3 trillion US dollars. It is predicted that the amount will reach 4.48 trillion US dollars(in 2021.) Some people object to this situation which could be described as a retail revolution. A male says, "I was one of those who became addicted to the convenience of online shopping and was purchasing almost everything online. But now, when I need something, I first think of going to a store to look for it." A female says, "The goods which are delivered are sometimes different from what I had in my mind. As it is troublesome to send them back, I end up using something that I do not really like. If I buy things at stores, such a situation does not happen so often. I will not buy unnecessary things, so I will not regret shopping. Therefore, recently I seldom shop online, and instead buy things at stores after seeing them directly." 9 Comments Newest Jennifer Frazer 20 June 2019 9:32AM /10 I also bought too many things online before, but now I have come to order only necessary things. The point is how to control yourself. As there are few shops in my neighborhood and there are plenty of goods on the Internet, I will continue to use the Internet for shopping. (★およそ280 words) 問1 According to the article, the total sales of online retail will 1 at 0 0 be four times as large as in 2017 ② be less than 1.66 billion US dollars decrease by about half in four years ④ increase to nearly twice as much in four years 問2 ①②③④ (2点) Your team will support the debate topic. "It is better to buy things at stores than to buy through the Internet. In the article, one opinion (not a fact) helpful for your team is that people 2 can buy only necessary things online 2 might be given a discount at a store 3 might buy unnecessary things at a store tend to buy unnecessary things when shopping online 1 2 3 4 (2点) esc 3 The other team will oppose the debate topic. In the article, one opinion (not a fact) helpful for that team is that 3 0 it is possible for you to shop comfortably online it takes some time for the goods ordered online to arrive 3 people can return the delivered goods if they do not like them people have to pay transportation fees to and from stores ① ② ③ ④ (2点) 7-2 © Z会 2025 [不許複製禁転載]

Resolved Answers: 1
Physics Senior High

物理の単振動の質問なのですが、 このスライドの内容は合っているでしょうか? またAiに質問すると紫マーカーで囲ってる部分がkxではなく−kxになると言われたのですが どこで間違っているのかわからず、教えてもらいたいです🙇 読んで頂いてありがとうございます。

単振動の解き方パターン (鉛直バネ振り子) ステップ1: つりあいの位置 (振動の中心) を決める mg 。 自然長からの伸びを 『』 とすると、つりあいの式はmg-kr=0よりです。 。 このつりあいの位置を原点=0と定めます。 ステップ2: 運動方程式から角振動数と周期を求める 力の釣り合いの位置より下にあるとき つりあいの位置からの変位をとすると、 運動方程式は以下のようになります。 鉛直バネ振り子への応用 1. 中心 自然長から。 伸びた「つりあいの位置」を0とする。 (つりあいの式: mg=kx) 2. 立式: ma=mgk(x+1) →mg=kro を代入するとma=kz になり、 水平と完全に同じ式になる! さっきやったやつ 単振動では下向きを正に取ったほうが圧 倒的にわかりやすい この「ma-kzに帰着する」 という感覚さえ残しておけば、1つの解法パターンで水平 鉛直の両方を完璧にカバーでき す。 素の位置を 〇にしたと ma=mg-k(x+x)= (mg-ko-kz ・つりあいの式 (mg-kx=0) より重力項が消えるため、 力のつりあい 質量 k → ma=-kz a=- T m 力の釣り合いの位置より上にあるとき 。 ma=mg-k(x-π) = (mg-ko)+kz ここで、つり合いの式mg-kr=0より重力項と自然長のばねの力は消えるため、 ma=kx (W=-) K 。 単振動の加速度の式αと見比べることで、ω= - が求まります。 m ° ばね振り子:2 2π m 周期はT= =2 1 と計算できます。 K or ° 華り子ィア2F1 ステップ3: 時々刻々の位置・速度・加速度を求める これは覚える 。 12=Asin wt Xmax = A L 。 速度=AwcoswtVmyAw=AW Loswt] Les | 加速度=Awzsin wtware AW=-Aw sinnt (A sin wt) つりあいの 位置 ©のとき T 5k (x+2) ma-mg-k(Y) ma-mg-k(x+2 F<0 KX6 ma mg 「力のつりあいの式 -kd+mg=0 F=-k (s+d)+mg r 110 a 変位 9:0までのキョリではなく バネの伸びなので才じゃなくて x+Xo ° 初期条件(t=0で端か中心か) に合わせて三角関数を選び、 数値を代入します。 ⑥ 変位の時間変化 Asinot 13 Asin of P A 409 A 0 明 ¥0.4 V. V. V. V 7 + TT

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