ページ1:

EKSPONEN
2-
qf(x)
1.
Sifat
am.
2. a
an
a
m+n
m-n
= a
3.
(am)n
m.n
= 9
4. (a.b)
5.
6.
a
m
q'm
7.
aᵒ
8.
9.
9
m/n
9%
= a' b
=
.
am/bm
½am
= 1
=
a'
9
E
9 70
10.
II.
12
√a
√9156
V.p
13.
14.
a
=
Fungsi
f(x)
= 9
a
= Sab
= a
=
√96
=
"Jap
=
"Sap
Ket:
a
=
bilangan pokok
x : Variabel
y
=
f(x) =
nilai fungsi
contoh!
O f (x) = 2*
→f(2) 22
→ f()
=
=
=
4
2½
Persamaan
f(x)
1. a
•
= 9
② f (x) = 3
Syarat = 9>o, a #1
= f(x) = m
• solusi
• contoh=
2
3x-1
3x-1
3-x
->
→f (2)
33-2
= 3
= 32
: 25
syarat
• solusi
• Contoh
f
@.greentealatte
99(x)
aso, 9 #1
f(x) = 9 (x)
3x-1
× +2
=
2
4
3x-1
+2
2
=
(22)
2x+4
23x-1
= 2
73x-1 = 2x+4
3x 2x4+1
x = 5
3.
19f(x)
• syarat.
= b f(x)
"
9 % b
• Solusi
f(x) = 0
• Contoh
3-X
3-×
= 7
3-×
= 0
3
= X
pertidaksamaan
bilangan pokok a tanda tetap
af(x) a
9(x)
af(x) a
9(x)
f(x) > g(x)
f(x)
9 (x)
tanda berbalik
2. bilangan pokok okali
qf(x)
> 99(x)
f(x) ≤ 9 (x)
9ffx) <99(x)
f(x) > g(x)
1)
Contoh :
tentukan Hp dari
2x +1
≤ 32
2
72x+1
32
2x+1
2
≤ 2'
2x+1
≤ 5
2× 4
X ≤ 2
HP: {x2}
2) tentukan Hp dari
2
x+5
≥ 4
<+5
(1) ** > 4
=2
x+5 < -2
×
≤ -7
Hp: {}
Sumber: guru
GELATIK
@greentealatte