読みましたが、全体的に理解出来ません。英語で理解出来なかったので多分、全文和訳しても理解出来ません。 なので、この写真に載っていることを分かりやすく教えていただきたいです🙇🏻‍♀️

Free energy changes determine if a reaction is endothermic or exothermic. Processes in nature are driven in two directions: toward least MAIN IDEA enthalpy and toward greatest entropy. When these two oppose each other, the dominant factor determines th direction of change. As a way to predict which factor will dominate fora given system, a function has been defined to relate the enthalpy and entropy factors at a given temperature tropy and constant pressure. This combined enthalpy-entropy function is callepd t free energy, G, of the system; it is also called Gibbs free energy. This function simultaneously assesses the tendencies for enthalpy and entropy to change. Natural processes proceed in the direction that lowersthefree energy of a system. Only the change in free energy can be measured. It can be defined in terms of changes in enthalpy and entropy. At a constant pressure and temperature, the free-energy change, AG, of a system is defined as the difference between the change in enthalpy, AH, and the product of the Kelvin temperature and the entropy change, which is defined as TAS. Free Energy Change AGO= AH°- TASO Note that this expression is for substances in their standard states. The product TAS and the quantities AG and AHhave the same umor usually kJ. The units of AS for use in this equation are usually N If AG<0, the reaction is spontaneous. AH and AS in the free-energy equation can have positive or negative values. This leads to four possible combinations of terms.

高3です。 129(ウ) 複雑な酸化還元で酸化剤と還元剤を判定する問題が分かりません。どこくらいで直感的に分かりますか？？ 二クロム酸カリウムは酸化剤で暗記かと思いますが...

(B FaCrnlgt4Hes0atうけ202つK2SOgtCralSO4l3 +9H20+302

【英語ですみません】最後の12番は何を書いたら良いのでしょうか…？ Video C の実験では、aqueous solution にlead(ii) nitrate, aqueous solution にPottasium iodide を入れていました。 2KI (aq)... 続きを読む

With lead (I) nitrate solution. This precipitation reaction produces a bright yellow solid. (point values in parentheses) Part 1: 1. Copy the unbalanced reaction below into your lab notebook. Balance the reaction by adding coefficients. (1) KI (aq) Pb(NO,), (aq) KNO, (aq) Pbl, (s) 2. a) Which trial are you assigned? b) Copy the data table below into your notebook. Watch video A (make sure it's the correct trial!) and collect your data. You may need to pause or rewatch the video, it goes quickly. (1.5) Mass of Empty Beaker (g) Mass of Beaker+ solid Pb(NO,)。(g) Volume of 1.0 M KI (aq) (mL) For the following calculations, show all your work for full credit. 3. What mass of solid Pb(N0,), was added to the beaker? (1) 4. If the solid Pb(NO,), was dissolved in 45 mL of water, what is the molarity of the Pb(NO,)。 solution? (2.5) 5. Which compound is the limiting reactant? (4) 6. What mass of lead (II) iodide (PbL,) should be produced? (2) Part 2: 7. Watch video B (make sure it's the correct trial!) to see the complete reaction and collection of the product. Copy the data table below and record your data. (1) Mass of filter paper (g) Mass of filter paper + dried precipitate (g) 8. What mass of precipitate was collected? Show your work. (1) Calculate the percent yield for the reaction. Show your work. (2) 10. For your trial, which three ions were present in the filtered solution at the end of the reaction? In other words, which three ions are still dissolved at the end of the reaction? Defend/explain your 9. answer. (3) 11. Watch video C - watch both tests for your trial and record your observations. (1) a) Add lead (II) nitrate - b) Add potassium iodide - 12. These tests were conducted to prove the identity of the limiting reactant. Considering your answers to the previous two questions, describe how these tests support the prediction you made in question 5 about which compound is the limiting reactant. (2)

【問題英語ですみません】どの様に解くのでしょうか。授業中を休んでしまい、問題の意味が良くわからなくなってしまいました…どなたか説明お願いします😭🙇‍♂️🙇‍♂️ 問題文の中に~M (molarity) が二つ出て来るのですが、その二つをどの様にして使い解くのでしょうか…文... 続きを読む

0c045L (L -01086 8. To what volume to you need to dilute 50.0 mL of a 2.00 M stock solution to get a 0.095x- X- D.91 95.2 mLy 0(095 |000 mL 9. How much deionized water do you need to add to 30. mL of 7.0M NaOH to make a solution that is 3.0 M? What total volume will you concentration of 0.500 M? うす have? I nol D03L 7mo. 0almol IL 0.1 imol 10. What volume of 2.00 M stock solution do you need to make 125 mL ofa 0.010 M solution? 11. What is the concentration of a solution made 0.01mol by diluting 55.6 mL of 3.0 M NaNO, to a new volume of 250 mL? 2L mo ニ IL 0、12JL スー1,25x10-mol 12. Express the concentration of the following solutions using mass percent. a) 0.025 niol of magnesium sulfate are dissolved in b) When all the water is boiled off from 3.4 lb of 100. mL of pure water. seawater, 14 oz. of salt remains

高3です (1)フラスコ内の液体が蒸発、凝縮する流れのところで 質量変化が結局どうなるのかを教えて欲しいです。 凝縮した分空気の質量も減らないのでしょうか？

°52. (液体の分子量の測定〉 下の限 いに答えよ。気体定数 R=8.31×10° Pa·L/(mol·K), H=1.0, C=12, 0=16 アルミ箔温度計 C, H, Oからなる沸点56°℃の化合物Xについて, 次の実験1~①を行った。 0 アルミ箔,輪ゴム, フラスコの質量を測ると 258.30g 8.90 輪ゴム であった。 ② フラスコに5mL の化合物 X を入れた。 ③図のように,フラスコの口にアルミ箔と輪ゴムを用い てふたをし,釘で小さな穴を開けて, 沸騰水中にできる だけ深く浸した。 の化合物Xが全部気化したことを確かめた後,しばらく して温度を読むと100°℃であった。 ⑤ フラスコを取り出して放冷した後,外側の水をふき取り,ふたをつけたまま質量を 測ると 260.40gであった。 ⑥ フラスコの内容積は1.11 L であり,その日の気圧は 1.01×10° Pa であった。 の元素分析を行ったところ, 化合物 Xに占める炭素と水素の質量百分率はC6..1% H10.3%であった。 フラスコ 沸騰水- 0 (1) 理想気体の状態方程式を用いた計算式を示し,化合物Xの分子量を有効数字3桁 まで求めよ。 (2)実験①の結果から, 化合物 X の組成式を求めよ。 準°53 ヨへー

高3です。 (9)極性引力で考えた時...周期表の右上ほど電気陰性度がつよいので分子間の極性が強くなる。よって周期表の上からHCl>HBr>HIだと思いました。 なぜ違うのか教えて欲しいです🙇‍♂️🙇‍♂️

(9)沸点の高い順に物質を左から並べよ。 HCI HBr m HIOX9S HF 出 上 シト

【英語ですみません】stoichiometry CH4と2O2 のどちらが先になくなりますかって言う問題だと思うのですが、計算式の意味がよくわからないです。一つ目は、reality で、2つ目はimpossible って描いてあるので上のやつで計算するとおもうのですが、ど... 続きを読む

CHy 202 CO2 + 2 H20 Example: I hae 3mal CHy and 7 mol Dz which will nn out frst? CHy lininng ranctant 1 -runs put PRED IしTIDNS. 3 mo CH) ICO2 3mol CO,<realty run out of CHy all the CHhy wull be usedu I CHy ICO1) チ mol O21 Con) 202 xcess rlachint impossible! dont have enouyh CHn =35mol CO2 < 3 more thon enoush Somcull 6c let4 ove/anused

至急回答お願いします！！💦 丸のついているところClNaって書いちゃ駄目なんですか？！

3 中和反応(1) p.6~ | (1) HCI + NaOH NaCl + HaO

【英語ですみません】3. a. b. c. がわかりません。 mole と amu、そしてこの単位を使うときのmolecules と atom の概念（？）がわかりません。 b. はやってみたのですが、他は問題がよくわかりません…どなたか説明お願いします🙇‍♂️🙏

Complete the following exercises to help you solidify your understand the utility of moles: The conversion factor given in the back of your book isl amu = 1.66 × 10-2/ kg. 10o0g This can be written as 1.66× 10-27 Kg ("kilograms per amu"). × Tkg amu 1. Change this conversion factor to grams per amu. 1,60xl0/amu 2. To get the number of amu per gram (the inverse), take the inverse of the number answer to #1 (divide 1 by that number). WRITE THE UNITS. -- do you recognize this number??! 3 amu kg 0gadols number 3. Since you have a conversion factor in amu(#1), you can convert from a mass in amu to one in grams. Do the following in order to demonstrate to yourself again what a mole is: a. How much does 1 molecule of SO, weigh in amu? b. How much does 1 molecule of SO, weigh in grams? 32,07+ 162)- 69.07g c. How muchdo 6.022 × 1023 (one mole of) SO, molecules weigh in grams? emoie n ftoe

【英語ですみません】14. 15. がわかりません。 14.はやってみたのですが、atoms と molecules じゃ違いますよね… ここからどうやってatomの数を計算したら良いのですか？ 15. イオンの数となると、Na の数を計算するのは違いますよね？ 説明よろし... 続きを読む

2.89 He helium Use what you know now to answer these questions. 40 L. COMGS 14. How many atoms are in 42.5 g of ammonia? alo1 13. How many molecules are in 42.5 g of ammonia? NH3 14.01 + l,01(3) - 17,04g/mol × 2,79mol -1,50Y10° 事 atomo 6,022x103 2.49 mol 15. How many Na* ions are in 4.8gofNa,SO,? 16. How many molecules are in 36.0 g of water? H.0 1,20×101mol 1o1(2)1 16 Jomo h - 18.02g/ma) YMA1O Complete the following exercises to help you solidify your understand the utility of moles: The conversion factor given in the back of your book is l amu= 1.66 × 10-27 kg. kg ("kilograms per amu"). This can be written as 1.66 × 10-27 amu 1. Change this conversi