Chemistry
Senior High
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有効数字の問題です。
①4.6+2.350
②3.52-2.1
③225×4.0
④6.02÷30.1
⑤5.6-0.224

5問、解説と答えをお願いします!!
ちなみに、有効数字のルールは分かっています。

Answers

✨ Best Answer ✨

①4.6+2.350=6.950有効数字2桁より7.0
②3.52-2.1=1.42有効数字2桁より1.4
③225×4.0=890有効数字2桁より8.9×10^2
④6.02÷30.1=0.2有効数字3桁より0.200
⑤5.6-0.224=5.376有効数字2桁より5.4

まっちゃ

ありがとうございます!!!!

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